[Paraview] copy-paste (or clone/dublicate) a filter
Samuel Key
samuelkey at bresnan.net
Mon Nov 18 09:32:39 EST 2013
Martina,
Regarding your question, I do not do this routinely, but it looks to me
that if you hold down the Ctrl-key and select two datum two sets and
then apply the Group Datasets filter you get a single combined datum
stream to which can apply the same filter to both using a single common
parameter specification. In a single view, this may require a coordinate
translation of one datum set with respect to the other in order that
they are not overlaid (use the Transform filter on one of the datum sets
before grouping). In addition, it is likely that the point and cell
variable sets for both objects need to be the same (except for the
values). Likely some care will be needed for the Slice and Clip filters
because you will only have a "single" object after grouping.
Hope this helps.
Sam
On 11/18/2013 1:39 AM, Martina Schäfer wrote:
> Hi all,
>
> I'd like to copy-paste (or clone/dublicate) a filter in paraview, i.e.
> applying exactly the same filter on two different sources without
> having to redefine the filter. For the moment I'm doing that via
> save-state/load-state and adjusting each time the input file (or via
> "change input" to a filter), but it would be more convenient to be
> able to have the results of the filter applied to the different
> sources at the same time to compare them side by side.
> That concerns for example the "clip" or "slice" filter where it would
> be really handy not having to copy by hand the definition of the plane
> used; or when doing a plot with isolines I'd like to have the same
> line "elevations" and drawing options for various input datasets.
>
> According to the various websites and also messages in this mailing
> list, "copy" and "paste" from the menu "edit" or with the
> mouse-left-click should work. However, when I do "paste" nothing happens.
> Has anybody experience with that? Is there any other way to do it? Or
> is there any "trick" how to do use the "paste function?
>
> Thanks a lot!
>
> Martina Schäfer
>
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