[vtkusers] vtkHyperOctree DeepCopy seems to actually be shallow
Trevor Irons
trevorirons at gmail.com
Tue Jan 15 17:44:52 EST 2013
Hello. I am having a problem with the vtkHyperOctree->DeepCopy method. The
underlying CellTree is being shallow copied.
I made the following modification to vtkHyperOctree.cxx:112
//-----------------------------------------------------------------------------
// because the PrintSelf test is not smart, PrintSelf has to be here.
void vtkHyperOctree::PrintSelf(ostream& os, vtkIndent indent)
{
this->Superclass::PrintSelf(os,indent);
os << indent << "Dimension: "<<this->Dimension<<endl;
os << indent << "Size: "<<this->Size[0]<<","<<this->Size[1]<<",";
os <<this->Size[2]<<endl;
os << indent << "origin: "<<this->Origin[0]<<","<<this->Origin[1]<<",";
os <<this->Origin[2]<<endl;
os << indent << "DualGridFlag: " << this->DualGridFlag << endl;
os << indent << "CellTree Ptr " << this->CellTree << endl; // stream
pointer address
//this->CellTree->PrintSelf(os,indent);
}
Just to check the address of the underlying tree. Then in a piece of (c++)
code
vtkHyperOctreeSampleFunction* OctSamp2 =
vtkHyperOctreeSampleFunction::New();
vtkHyperOctree* Octree = vtkHyperOctree::New();
// Do the sampling
this->Octree->DeepCopy(OctSamp2->GetOutput())
std::cout << *OctSamp2->GetOutput() << std::endl;
std::cout << *Octree << std::endl;
And the two pointer addresses were the same.
OctSamp2-> GetOutput() ->>>>> CellTree Ptr 0x237fcf0
Octree - ->>>>> CellTree Ptr 0x237fcf0
Which I did not expect, and is causing errors in my application. Is there
a way to get a true deep copy?
If this is indeed an error I can generate a test file exhibiting the
problem. But my method of checking involved mucking with the vtk source
file.
Thanks for any help or input.
-- Trevor
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://www.vtk.org/pipermail/vtkusers/attachments/20130115/3ef61fda/attachment.htm>
More information about the vtkusers
mailing list