[vtkusers] generating walls of a room.

[Fred Fred]

Might vtkCubeSource be a solution to your problem?

> Date: Tue, 3 Nov 2009 21:55:08 +0000
> From: anja.ende at googlemail.com
> To: vtkusers at vtk.org
> Subject: [vtkusers] generating walls of a room.
> 
> Hello,
> 
> I had made a post about a room design application where I would have
> various vtkActors rendering different bit of furniture geometry that I
> would import from a CAD application.
> 
> My question was about designing the geometry of the room and how I can
> simulate the 6 walls of a 5 x 5 x 5 room and have a vtkCamera so that
> I can change the view perspective.
> 
> I realize that I might not have asked the question in more detail, so
> I would attempt again. I certainly hope  someone can help me with the
> vtk side of things.
> 
> So, what I was thinking was that the 6 walls can be represented by 8
> corner points. If we assume that:
> - x increases from left to right.
> - y increases from bottom to top
> - z increases from screen to viewer.
> 
> The the 8 corner points would define the wall geometry. Now, I would
> also like to attach physical meaning to the dimensions. So, if my wall
> is 5 m x 5 m x 5m, I am guessing the vtk data structure can hold this
> information and allow me to go seamlessly from screen coordinates to
> real world coordinates.
> 
> My question is how do I set all this up in vtk and render it. I would
> like to set the walls so that the axes values go from -1 to +1. I
> guess I could easily convert from screen (int) coordinates to real
> world and vice versa.
> 
> I am guessing I could use a combination of vtkPlane objects to create
> this scene but have no idea on how to go about it. What data structure
> should I use for holding my wall parameters (vtkDataSet,
> vtkRectilinearGrid??).
> 
> Also, if I want to set the origin at a certain arbitrary point in the
> room, how do I go about it?
> I hope this is a bit more clear. As you can imagine, I am completely
> lost on the VTK side of things. I would really appreciate any help
> anyone can give me.
> 
> Many thanks,
> 
> Anja
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