[vtkusers] mixing vtkImageActor with solidly rendered vtkPolyData

[dean.inglis at camris.ca]

Hi Mathieu,

thanks for your quick reply!  
Yes, the polydata are all on the same layer as the image.
I would like to know why the contour lines show since they are
also in the same plane as the image (and the polygon) 
but the polygon will not?  The polygon actor is only
visible when rendered in wireframe mode.

Dean

> Subject: Re: [vtkusers] mixing vtkImageActor with solidly rendered
>  vtkPolyData
> 
> Hi,
> 
> Is the polydata on the same layer as the image? I mean,
> if the image origin is (originX, originY, originZ), the
> polydata origin should be closer to the camera in the
> direction of projection to make sure it is always visible.
> Otherwise it may appear or not if they are defined at the same
> position.
> 
> I usually define an epsilon value to the polydata to put in
> front of an image. If my image is at (originX, originZ, 0), I put my polydata
> position as (posX, posY, epsilon).
> 
> Hope it will help...
> 
> Thanx.
> 
> MAthieu
> 
> --
> > >
> >in a renderer I have a vtkImageActor (ivar of vtkImageViewer2)
> >showing a slice of a 3D image.  On top of that are
> >two vtkActors rendering 2D contours (vtkPolyData lines) from a
> >segmentation and
> >another actor rendering a 2D filled segmentation region (
> >vtkPolyData solid polygon).  When I scroll through the slices,
> >each slice's contour lines and polygonal region are
> >updated.  I can see the lines but the polygons appear
> >briefly and then disappear.  If I hide the vtkImageActor,
> >the polygons are clearly there.  If I set the polygon actor
> >to render as a wireframe, the region is correctly shown as a triangulated
> >polygon whether or not the image actor is visible or not.
> >If I toggle between wireframe and solid when the image actor
> >is visible, the solid polygon will not display: only the wireframe
> >representation will.  SetCoincidentTopologyToPolygonOffset has no
> >effect.  How can I mix vtkImageActor with solidly rendered vtkPolyData?
> >
> >Dean
> >
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> 
> 
>