[vtkusers] release memory allocated in vtk from python

[David Gobbi]

A shallow copy should be sufficient:

def test(filename):
   r = vtkgdcm.vtkGDCMImageReader()
   r.SetFileName(filename)
   r.Update()
   img = vtk.vtkImageData()
   img.ShallowCopy(r.GetOutput())
   return img

Or, to be even more minimalist, copy just the pixel data and nothing else:

def test(filename):
   r = vtkgdcm.vtkGDCMImageReader()
   r.SetFileName(filename)
   r.Update()
   img = vtk.vtkImageData()
   img.CopyStructure(r.GetOutput())
   img.GetPointData().PassData(r.GetOutput().GetPointData())
   return img

 - David

On Mon, Jul 2, 2012 at 10:17 AM, Jothy <jothybasu at gmail.com> wrote:
> I think the first one.
>
> Jothy
>
> On 02-Jul-2012, at 5:06 PM, José M. Rodriguez Bacallao <jmrbcu at gmail.com> wrote:
>
>> hi folks, how to correctly release memory using vtk from python
>> for example, which one of this three code snnipets release the memory
>> allocated when reading the file:
>>
>> def test(filename):
>>    r = vtkgdcm.vtkGDCMImageReader()
>>    r.SetFileName(filename)
>>    r.Update()
>>    img = vtk.vtkImageData()
>>    img.DeepCopy(r.GetOutput())
>>    return img
>> --------------------------------------------------------------------------
>> def test(filename):
>>    r = vtkgdcm.vtkGDCMImageReader()
>>    r.SetFileName(filename)
>>    r.Update()
>>    return r.GetOutput()
>> ---------------------------------------------------------------------------
>> r = vtkgdcm.vtkGDCMImageReader()
>> r.SetFileName(filename)
>> r.Update()
>> img = r.GetOutput()
>> img = None
>> del img
>> r = None
>> del r
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