[vtkusers] Get all the bounding boxes

[Jalal Miftah]

Hi,

Given a point cloud, you have an infinity of bounding boxes (if you 
translate/rotate the point cloud for example), that what I mean for "all 
the boxes".
I am not looking for the smallest possible, but something in between (the 
distance between my point cloud and one surface of the bounding box should 
be minimum). But yes basically I need to find one box among all of them.

Hope this is better.

Thank you

Jalal 



From:   David Doria <daviddoria at gmail.com>
To:     Jalal Miftah <jalal.miftah at amadeus.com>, vtkusers at vtk.org
Date:   27/10/2011 14:49
Subject:        Re: [vtkusers] Get all the bounding boxes



On Thu, Oct 27, 2011 at 9:46 AM, Jalal Miftah <jalal.miftah at amadeus.com> 
wrote:
Hi, 

Thanks for you reply. 
Indeed I want a single bounding box for all my point cloud, let me explain 
: 
I have a point cloud, and I have to find, among all the bounding boxes, 
the correct one (it's not necessarily oriented in the same direction of 
the axis). I know how to determine the right one. 
Now I need to find a way to get all the bounding boxes. 
For now I was rotating my point cloud and computing a new bounding box 
each time, but it's not really perfect. 
I tried vtkOBBTree, but I have an eigenfunction issue. (I have this inside 
my vtkPolyData : 

vtkPoly->SetPoints(points); // vtkPoints * (xyz data) 
vtkPoly->SetVerts(conn); // vtkCellArray * 
vtkPoly->GetPointData()->SetScalars(colors); // vtkUnsignedCharArray * 
(rgb data) 

 ) 

Do you need more explanations? 

Please keep the discussion on the mailing list.

vtkOBBTree will generate a hierarchical tree of boxes, so I don't think 
that's what you're looking for. Are you are trying to determine the 
smallest possible bounding box of the points? I still don't understand 
what you mean by "all the boxes".

David




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