[vtkusers] What exactly happens in this scenario?

[Bill Lorensen]

You need not remove it from the renderer. The renderer as part of its
destructor will UnRegister() it's actors. Once the ref count of the
actor goes to 0, it will be deleted.

On Sat, Jun 26, 2010 at 12:29 PM, Rakesh Patil <rakeshthp at in.com> wrote:
> hi,
>
> thanks.. then wat about the actor?? should it be removed from the renderer
> and then, deleted or
> if i delete, it is directly removed from the renderer??
>
> Thanks
>
> ---------- Original message ----------
> From:"Bill Lorensen"< bill.lorensen at gmail.com >
> Date: 25 Jun 10 18:23:59
> Subject: Re: [vtkusers] What exactly happens in this scenario?
> To: logic_cube <John.Fraser at icr.ac.uk>
>
> In the destructor? Technically, yes. But it won't matter.
>
> On Fri, Jun 25, 2010 at 8:51 AM, logic_cube <John.Fraser at icr.ac.uk> wrote:
>>
>> Shouldn't it be like this?
>>
>> if (elementNumberActor != NULL)
>> {
>> elementNumberActor->Delete();
>> elementNumberActor = NULL;
>> }
>>
>>
>>
>> Bill Lorensen-2 wrote:
>>>
>>> Yes, it will leak.
>>>
>>> To prevent the leak,, in your constructor,
>>> elementNumberActor = NULL;
>>& gt;
>>> In DisplayElementNumbers() before assigning the actor,
>>> if (elementNumberActor != NULL)
>>> {
>>> elementNumberActor->Delete();
>>> }
>>>
>>> In the destuctor,
>>> if (elementNumberActor != NULL)
>>> {
>>> elementNumberActor->Delete();
>>> }
>>>
>>>
>>
>> --
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>>
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