[vtkusers] Linear interpolation as implemented by vtkImageReslice
Luca Pamparana
luca.pamparana at gmail.com
Wed Sep 19 08:46:56 EDT 2007
Hi David,
Many many thanks for answering my question! I am really grateful.
Yes, you are right I see that the number of pixels generated are correct.
However, I am unable to figure out what the algorithms are doing to generate
the values.
For example, I created a small synthetic image (unsigned char) type with the
following pattern. Origin is at lower left (image dimension 5 X 5):
2 3 4 5 0
3 4 5 0 1
4 5 0 1 2
5 0 1 2 3
0 1 2 3 4
switched to linear interpolation with the image and on zooming by a factor
of 2, I get the following pixel blocks:
2 2 3 3 4 4 5 4
1 0
3 3 3 4 4 4 3 2
1 1
3 3 4 4 5 4 1 0
1 1
4 4 4 4 3 2 1 1
1 2
4 4 5 4 1 0 1 1
2 2
5 4 3 2 1 1 1 2
2 3
5 4 1 0 1 1 2 2 3
3
3 2 1 1 1 2 2 3
3 4
0 0 1 1 2 2 3 3
4 4
0 0 1 1 2 2 3 3
4 4
What I want to know is how this is calculated? Could you, by any chance,
tell me the formula and the process as which pixels are considered when
calculating the intermediate values and what happens with the edge pixels? I
see the first two rows are exactly the same.
Also, what about cubic interpolation? Is it something similar as well?
I am attaching an image of the output, so you can see the pixel blocks. If
you load it in GIMP than you can easily see each pixel and see the intensity
value with the color picker tool...
Again, I will be really grateful for all your help.
Thanks,
Luca
On 9/19/07, David Gobbi <david.gobbi at gmail.com> wrote:
>
> Hi Luca,
>
> To see how vtkImageReslice zooms an image by a factor of 2, you
> should be doing something like this:
>
> vtkPNGReader *reader = vtkPNGReader::New();
> reader->SetFileName("myfile.png");
> reader->SetDataSpacing(1.0, 1.0, 1.0); // tell VTK what pixel spacing to
> use
>
> vtkImageReslice *reslice = vtkImageReslice::New();
> reslice->SetInput(reader->GetOutput());
> reslice->SetOutputSpacing(0.5, 0.5, 0.5); // resample with zoom factor of
> 2.0
>
> If you write the output of this reslice to a file, you will see
> exactly what you expect, i.e. a new pixel inserted between all
> the old pixels in both the vertical and horizontal directions. So if
> the original image size was 100x100, the new image will be
> 199x199 because 99 new pixels have been inserted in the
> horizontal and vertical directions.
>
> Since this is not what you are seeing, then there might be something
> wrong with the way you are appying the zoom factor. If you can send
> a few lines of code that show how you are using vtkImageReslice, that
> would help me to fully answer your question.
>
> Cheers,
>
> David
>
>
> On 9/19/07, Luca Pamparana <luca.pamparana at gmail.com> wrote:
> > Hi everyone,
> >
> > I had asked this question a few days back but did not receive any help.
> > Asking it again hoping someone would answer my query!
> >
> > Just trying to understand the linear interpolation algorithm as
> implemented
> > in the vtkImageReslice class. I tried looking at the source code but it
> is
> >
> > really complicated and I could not understand much :(
> >
> > Anyway, I am zooming my image by a factor of 2. The image is a synthetic
> > image which has a thick edge going along its diagonal (the value is
> changing
> > from 0 to 255) and I am trying to look at how the values are
> interpolated in
> > that region.
> >
> >
> > One thing I noticed is that there are 2 pixels being inserted in the
> > horizontal direction. So, I get the values 255, 191, 64 and 0 (255 and 0
> are
> > the old values and the two new values are being generated by taking a
> > weighted average). Is this correct? I thought that if I zoom by a factor
> of
> >
> > 2.0 than one pixel should be inserted between successive pixels. I am
> not
> > sure what happens at the edge pixels though.
> >
> > Also, what happens in the vertical direction? I cannot really figure out
> how
> > this works...
> >
> >
> > So if I have pixel values as follows:
> >
> > 255 0 1 2
> > 0 255 0 1
> >
> > How is the lienar interpolation being done on a zoom of 2.0?
> >
> > I would really appreciate it if someone can clarify these doubts for
> me....
> > I have spend a lot of time trying to understand this but have not yet
> been
> > able to comprehend this implementation.
> >
> >
> > Thanks,
> >
> > Luca
> >
> > _______________________________________________
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