[vtkusers] vtkTransform and Rotations !!

Sebastien Auclair sxa at fluent.com
Thu Mar 27 15:20:11 EST 2003


Hum... That too isn't working....

Then i get :

X= 1.27222e-014
Y= 90
Z= -90
...again from initial angles:
X=90
Y=90
Z=0

Thanks !
____________________________________
Seb

----- Original Message -----
From: "Glen Lehmann" <glehmann at imaging.robarts.ca>
To: "Sebastien Auclair" <sxa at fluent.com>
Cc: <vtkusers at public.kitware.com>
Sent: Thursday, March 27, 2003 3:16 PM
Subject: Re: [vtkusers] vtkTransform and Rotations !!


> Hi Sebastien,
>
> vtkTransform performs rotations in the ZXY order.  If you do something
like;
>
> newTransform->RotateZ(Rz);
> newTransform->RotateX(Rx);
> newTransform->RotateY(Ry);
>
> then GetOrientation() will will return what you expect.
>
> I hope this helps you out,
> Glen
>
> Sebastien Auclair wrote:
>
> >Hi folks !
> >
> >I need to create a rotation matrix for x,y and z . (Please note that we
> >aren't using vtkActor for transformation...neither vtkWindowInteractor
...)
> >
> >I have read every post in the usergroup's repository and nothing really
> >helped.
> >
> >The problem is that GetOrientation never produces to correct result.
> >
> >This is essentially how I do it :
> >##################################################################
> >vtkMatrix4x4 *matrix = vtkMatrix4x4::New();
> >vtkTransform* newTransform = vtkTransform::New();
> >newTransform->Identity();
> >newTransform->PostMultiply();
> >newTransform->Translate(-(m_origin[0]), -(m_origin[1]), -(m_origin[2]));
> >
> >newTransform->RotateWXYZ(y, 0,1,0);
> >newTransform->RotateWXYZ(x, 1,0,0);
> >newTransform->RotateWXYZ(z, 0,0,1);
> >newTransform->Translate((m_origin[0]), (m_origin[1]), (m_origin[2]));
> >float test[3] ;
> >newTransform->GetOrientation(test);
> >##################################################################
> >For exemple,  if we try to rotate with (X=90, Y=90, Z=0), we get
orientation
> >(X=90, Y=0, Z=90).
> >And what is the difference between RotateX and RotateWXYZ (a, 1, 0, 0)
> >??????
> >
> >
> >Thanks for any help.
> >___________________________________________________
> >Seb
> >
> >_______________________________________________
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> >
> >
> >
>
>
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