[Paraview] Extract region enclosed by isocontour surface and slice

[Shuhao Wu]

That works great! Thanks!

Shuhao

On 2017-09-01 12:45 PM, Ross Gardiner wrote:
> Not sure. The Glyph filter might work?
> 
> - Ross
> 
> On 01/09/2017, 17:10, "Shuhao Wu" <shuhao at shuhaowu.com> wrote:
> 
>      Thanks for the help! That worked like a charm.
>      
>      One more question: after I extracted my point of maximum via a
>      programmable filter, I have a PolyData of 1 point only. Is there a way
>      to display this point in the 3D render view? I can't seem to get the
>      point to render via a Geometric Representation.
>      
>      Thanks,
>      Shuhao
>      
>      On 2017-09-01 08:44 AM, Ross Gardiner wrote:
>      > I think you might be able to use the ‘Clip’ filter instead, with the Clip Type set to Scalar. Instead of giving you an isosurface, this will give you the region bounded by an isosurface.
>      >
>      > Thanks,
>      > Ross
>      >
>      > On 31/08/2017, 23:00, "Shuhao Wu" <shuhao at shuhaowu.com> wrote:
>      >
>      >      Hello all,
>      >
>      >      I'm trying to find a maximum value in a region that's enclosed by an
>      >      contour. I've attached an example of this, where the region of interest
>      >      is within the black box and the grey surface. Of course, I would first
>      >      filter the data to be bounded by the black box before proceeding to
>      >      calculate the maximum value.
>      >
>      >      I'm not sure if there is an automated way to do this. My idea is to
>      >      extract the region based on the intersection of the outer most contour
>      >      surface. After extracting the region, I can then find the maximum value
>      >      and location fairly easily.
>      >
>      >      However, I'm unsure how I can accomplish this as I don't see a filter
>      >      that offers functionality like this as it would rely on two input: the
>      >      contour and the original data.
>      >
>      >      Any advice on this would be greatly appreciated.
>      >
>      >      Thanks,
>      >      Shuhao
>      >
>      >
>      
>