[Paraview] Creating a surface along a complex path

[Tim Gallagher]

Hi Utkarsh,

I actually found that this morning when I compiled a later version of PV than the one I was using previously (our clusters are behind on dependencies so I've been reluctant to try and upgrade). 

Thanks,

Tim

----- Original Message -----
From: "Utkarsh Ayachit" <utkarsh.ayachit at kitware.com>
To: "Tim Gallagher" <tim.gallagher at gatech.edu>
Cc: "ParaView list" <paraview at paraview.org>
Sent: Monday, November 23, 2015 10:32:24 AM
Subject: Re: [Paraview] Creating a surface along a complex path

Is this what you're looking for: http://www.kitware.com/blog/home/post/725

Utkarsh

On Fri, Nov 20, 2015 at 2:51 PM, Tim Gallagher <tim.gallagher at gatech.edu> wrote:
> Hi,
>
> I had an idea I would like to explore but I'm not sure the right way to do it. I have a 3D vtkMultiblockDataset that is composed of curvilinear structured blocks. Let's say I create a line source with s = f(x,y,z). This line source can have a normal vector at each point that is confined to a particular plane (so for example, if I have s = x @ y = 0, z = 0 there are 2 normals of s confined to the x-y plane -- (0,1,0) and (0,-1,0)). I would like to create a slice where the local normal of the slice is oriented with one of those two normals (it doesn't matter which since a slice is infinitely thin).
>
> To give my actual example -- I have a fluid flow and I place a single streamline seed and generate the streamline. In this case, the streamline has constant z coordinates and is a function of x,y. This streamline represents the core of my flow. I would like to extract a slice whose profile (side view) is this streamline.
>
> And depending on whether that looks cool or not, I would like to try applying a ribbon to my streamline so I now get a rotated shape based on the local rotation in the flow, and then I would like to extract a slice that is locally normal to the ribbon.
>
> Is there a filter or set of filters that could do this? Do I need to figure out how to write my own to do it?
>
> Thanks,
>
> Tim
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