[Paraview] How to get the folder of the active source

[Cory Quammen]

Matheus,

activeSource.FileName

will get you the path to the file. This ought to work for most file readers.

os.path.dirname(activeSource.FileName)

will get you the directory.

HTH,
Cory

On Sun, Dec 6, 2015 at 11:05 PM, Matheus Viana <vianamp at gmail.com> wrote:

> Hi list.
>
> I was wondering whether it is possible to determine the folder where the
> active source was loaded from in a Python script.
>
> Thanks,
>
> *Matheus Viana*
> *Postdoctoral Research Employee*
> *Developmental and Cell Biology*
> *University of California Irvine*
>
>
>
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-- 
Cory Quammen
R&D Engineer
Kitware, Inc.
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