[Paraview] Rendering in Paraview

[Fastl, Thomas]

Hello,

thank you for the help so far, I really appreciate any input!

ad Cory's response: I totally agree, seems to be a classic thing in rendering and makes total sense to me. However, strange is that this happens only for the right half of the ellipsoid. Any ideas on that?

ad Sam's and Ken's response: I was thinking about doing that in Matlab during generation, but thanks for pointing out that I can do it pretty straight forward in Paraview directly, makes things easier.

Again, I think it is just a little bit strange that the rendering problem occurs only on one half of the ellipsoid, maybe someone has experienced something similar? Thanks!

Thomas
?
________________________________
From: ParaView <paraview-bounces at paraview.org> on behalf of Moreland, Kenneth <kmorel at sandia.gov>
Sent: Thursday, April 23, 2015 10:19 PM
To: Samuel Key
Cc: paraview at paraview.org
Subject: Re: [Paraview] Rendering in Paraview

If you want to use this approach, it is probably easier to use the transform filter and scale by 0.99 than use the calculator.

-Ken

Sent from my iPad so blame autocorrect.

On Apr 23, 2015, at 4:13 PM, Samuel Key <samuelkey at bresnan.net<mailto:samuelkey at bresnan.net>> wrote:

Thomas,

Assuming your x,y,z-origin is at the center of the ellipsoid, and you are using PV version4.3.1, you might be able to do the following:

If you want to display these two objects at the same time, use the "eyeball" in the Pipeline Browser to turn off the hex mesh, then use the Calculator filter just on the quad mesh to shrink its x,y,z-coordinates by, say, 0.99. This will "pull" the quad mesh just inside the hex mesh. You can then do whatever variable display you like on the objects.

If you are going to this display several times, the pipeline can be saved with Save State.

Sam


On 4/23/2015 12:21 PM, Fastl, Thomas wrote:

Hello Community,


I have a question concerning rendering in Paraview (Version 4.2.0). I have two .vtk files: i) an ellipsoidal volume geometry of hexahedral cells (cell type = 12) and ii) the internal surface of the ellipsoidal geometry represented using quadrilateral cells (cell type = 9). The first one is colored grey in the attached image, while the latter one is displayed in blue. Opening both of them at the same time leads to a quite confusing representation, which I don't really understand.


In the image attached the quadrilateral surface was opened first followed by the hexahedral volume. So I can understand why Paraview renders the left part in the color of the volume, but I do not get why it splits the rendering and is checkered on the right side? Is this an intended behavior or might I have made a mistake? I checked the coordinates of the points in both files and they are identical. Thanks!


Best, Thomas Fastl




_______________________________________________
Powered by www.kitware.com<http://www.kitware.com>

Visit other Kitware open-source projects at http://www.kitware.com/opensource/opensource.html

Please keep messages on-topic and check the ParaView Wiki at: http://paraview.org/Wiki/ParaView

Search the list archives at: http://markmail.org/search/?q=ParaView

Follow this link to subscribe/unsubscribe:
http://public.kitware.com/mailman/listinfo/paraview


_______________________________________________
Powered by www.kitware.com<http://www.kitware.com>

Visit other Kitware open-source projects at http://www.kitware.com/opensource/opensource.html

Please keep messages on-topic and check the ParaView Wiki at: http://paraview.org/Wiki/ParaView

Search the list archives at: http://markmail.org/search/?q=ParaView

Follow this link to subscribe/unsubscribe:
http://public.kitware.com/mailman/listinfo/paraview
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://public.kitware.com/pipermail/paraview/attachments/20150423/d1af3ca2/attachment.html>