[Paraview] Multi-views with multiple animated cameras

[Raymond.Cohen at csiro.au]

Hi Utkarsh,

I have been experimenting and I believe that the "add camera" option in the "Animation View" only adds a camera to the *newest* view and *not* the selected view as you would expect. If this is a bug it should be easy to fix.

I am using ParaView 3.8.0 32 bit on Windows.

Cheers,
Ray


-----Original Message-----
From: Utkarsh Ayachit [mailto:utkarsh.ayachit at kitware.com] 
Sent: Thursday, 7 October 2010 12:08 AM
To: Cohen, Ray (CMIS, Clayton)
Cc: paraview at paraview.org
Subject: Re: [Paraview] Multi-views with multiple animated cameras

Animation view shows/edits the camera animation track for the active
view. You cycle through all the views you have one after the other and
add camera animation tracks for each of them. Since Views are not
really named in the UI, even if we list all cameras in  the animation
view, it will hard for users to realize which camera is associated
with which view.

It's not possible to link individual camera properties using the GUI.
You can always code something up in Python to achieve similar effects.

Utkarsh

On Wed, Oct 6, 2010 at 2:49 AM,  <Raymond.Cohen at csiro.au> wrote:
> Hi,
>
> I would like to have two separate 3d views of my data that have a different
> moving camera in each.
>
> If I set up my scene with 2 views, then go to Animation view, it only allows
> me to add a single "Camera" animation which is only associated with one of
> the views. I have discovered a clumsy workaround which is:
>
> o start with 1 view
> o add a camera animation "Interpolate between locations"
> o split the view so there are now 2 views
> o add another camera animation "Interpolate between locations", which will
> be associated with the new view.
>
> May I suggest that in the "Animation view" add drop box that all the
> individual cameras are listed individually?
>
>
>
> On a separate note, is it possible for links between cameras positions to be
> done on individual elements of the ViewPosition (e.g. x/y/z)?
>
>
> Cheers,
> Ray
>
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