[Paraview] slice filter

Xian Sperber xian2paraview at googlemail.com
Mon Nov 29 11:01:13 EST 2010


My data were polydata although the vertices were organised as points instead
of 'real' polygones. After connecting these points through squares I was
able to apply the slice filter.

Thanks,
xian




On 25 November 2010 16:24, Andy Bauer <andy.bauer at kitware.com> wrote:

> Hi Xian,
>
> Please reply to the list so that everyone can participate in the
> conversation.
>
> As for your problem, how many cells and points are in the original image
> data set?  Did you change the location of the slice plane?  I believe by
> default the slice plane has a normal in the x-direction and is centered on
> the bounding box of the domain.  Did you hit apply after selecting the slice
> filter?
>
> If after checking these things you still don't get it working properly, can
> you share your data set?
>
> Andy
>
>
> On Thu, Nov 25, 2010 at 1:59 AM, Xian Sperber <
> xian2paraview at googlemail.com> wrote:
>
>> The image is a 3D image of x,y,z. The statistics in the information tab
>> says 'polygonal mesh', number of cells: 0, number of points: 0, and Memory:
>> 0 MB. I assume that means there is no data. However, the original image
>> which I ried to slice has definitely data.
>>
>> xian
>>
>> On 24 November 2010 20:06, Andy Bauer <andy.bauer at kitware.com> wrote:
>>
>>> Is the image a 2D image or a 3D image?  With the slice filter as the
>>> active filter (e.g. highlighted in the Pipeline Browser), how many cells are
>>> listed in the Information tab of the Object Inspector?
>>>
>>> Andy
>>>
>>>  On Wed, Nov 24, 2010 at 8:45 AM, Xian Sperber <
>>> xian2paraview at googlemail.com> wrote:
>>>
>>>>  Dear list,
>>>>
>>>> I have been trying to slice my image by a plane. However, whenever I
>>>> press the apply-button no sliced picture appears but only the emty box. My
>>>> data are displayed as points so that I thought the plane actually cuts
>>>> between the points. If this is the problem how can I convert my original
>>>> image into a surface? Could someone point me in the right direction?
>>>>
>>>> Cheers,
>>>> xian
>>>>
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>
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