[Insight-users] return a smart pointer

[Ivan Macia]

Hi Siqi,

Since the filter is going out of scope you should do

ImageType::Pointer img = filter->GetOutput();
filter->Update();
img->DisconnectPipeline();
return img;

Regards

Iván

2009/12/31 siqi chen <siqichensc at gmail.com>

> I dig into my old code and find that I used something like this before. Is
> this correct? How do I check the reference count?
>
> void main()
> {
> ImageType::Pointer image = fun();
> }
>
> ImageType::Pointer fun()
> {
> FilterType::Pointer filter = FilterType::New();
> ...
> ImageType::Pointer img = filter->GetOutput();
> filter->Update();
> return img;
> }
>
> Thanks
> Siqi
>
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