[Insight-users] Question about Euler2DTransform

[Albert Chitemyan]

  Hi,
   
  Thanks for your answers.
  It seems to me, I realized:
  The Euler2DTransform applies transformation first rotating, then translating, but resampler obtains output image by transforming output image into the input image, i.e. applies backward transformation
   
  Euler2DTransform  transformation
  [ x' ] = [ cos   -sin ] [ x ] + [Tx] 
[ y '] = [ sin    cos ] [ y ] + [Ty]
   
  backward transformation
    [ x ]  = [ cos  -sin ] [ x' - Tx ]
[ y ]  = [ sin   cos ] [ y' - Ty ]

   
  i.e. first translating the point, then rotating
   
  Am I right ?
   
  Thanks
   
  Albert
  
Zachary Pincus <zpincus at stanford.edu> wrote:
  Remember that a resampler uses a backward transformation from points 
in the destination to points in the source image. (As described in 
the software guide.) With this in mind, is the Euler transform still 
not working as described?

Zach Pincus

Program in Biomedical Informatics and Department of Biochemistry
Stanford University School of Medicine

On Nov 21, 2005, at 11:34 PM, Albert Chitemyan wrote:

> Hi,
>
> In ItkSoftwareGuide is written that in Euler2DTransform the 
> rotation is applied first, followed by the translation. But in 
> practice the opposite thig takes place. How can you explain it?
> Albert
>
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