[Insight-users] neighborhood of a neighborhood
Miller, James V (Research)
millerjv at crd . ge . com
Wed, 27 Aug 2003 17:16:45 -0400
This may be the same as Josh suggested:
The key here is that an iterator walks a prescribed region. So use two
neighborhood iterators. The first walks the full region of interest and
has a large radius. As the first iteration moves, you define a region off
this iterator (convert its location and radius to an start index and size
for a region, start index = location - radius, size = 2*radius+1). Define
a second iterator that walks this newly defined region.
outer_iter = NeighborhoodIteratorType(largeRadius,
this->GetInput(), largeRegion);
while ( !outer_iter.IsAtEnd() )
{
// these next two lines probably won't compile, but you get the idea.
smallRegion.SetIndex( outer_iter.GetLocation() - 2 * largeRadius );
smallRegion.SetSize( 2 * largeRadius + 1 );
inner_iter = NeighborhoodIterator(smallRadius, this->GetInput(),
smallRegion);
while ( !inner_iter.IsAtEnd() )
{
// do something
++inner_iter;
}
++outer_iter;
}
> -----Original Message-----
> From: Joshua Cates [mailto:cates at sci . utah . edu]
> Sent: Wednesday, August 27, 2003 1:21 PM
> To: John M. Galeotti
> Cc: insight-developers at itk . org; insight-users at itk . org
> Subject: Re: [Insight-users] neighborhood of a neighborhood
>
>
> Hi John
>
> One way to do this would be to define a region R and a neighborhood
> iterator N on R. You would have to "manually" iterate R through the
> image by incrementing its Index and modifying the Size. You
> could grab
> the Index from a regular iterator moving through the image.
>
> Josh.
>
> On Tue, 26 Aug 2003, John M. Galeotti wrote:
>
> > Is it possible to iterate a small neighborhood through a large
> > neighborhood which is itself iterating through a much larger image?
> >
> > John Galeotti
> > jgaleotti at cmu . edu
> >
> > _______________________________________________
> > Insight-users mailing list
> > Insight-users at itk . org
> > http://www . itk . org/mailman/listinfo/insight-users
> >
>
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