[Insight-developers] itkPoint itkVector additional methods
Miller, James V (CRD)
millerjv@crd.ge.com
Mon, 23 Jul 2001 07:52:01 -0400
Luis,
I think the SetToMedian() method needs to be renamed. Median has a strict statistical meaning which
is the middle point out of a sample of N (this is the definition for N odd. if N is even, the median
is usually defined as the midpoint between the two middle samples).
I think the SetToMedian() method should be renamed to SetToMidpoint().
Another way to provide this API is to not provide "Set" methods but rather class (static) methods
like
Point Point::MidPoint(Point &, Point &)
return a Point which is the midpoint of the arguments
Point Point::LinearCombination(Point &, Point&, float)
return a Point which is the linear combination of the specified points
Point Point::BarycentricCombination(Point &, Point &, float, float)
return a Point which is the barycentric combination of the specified points
I would also add a more general method:
Point Point::LinearCombination(Point [], float weights[], unsigned int num)
return a Point which is the linear combination or weighted average of a set
of points. I suppose this last one could be implemented using PointContainers
and iterators. I am tempted to call this method weighted average but that would
imply that the weights sum to one. I don't want to restrict the call to that case.
-----Original Message-----
From: Luis Ibanez [mailto:ibanez@choroid.cs.unc.edu]
Sent: Saturday, July 21, 2001 2:52 PM
To: insight-Developers
Subject: [Insight-developers] itkPoint itkVector additional methods
According to what we discuss in the Tcon,...
itkVector has now a Normalize() method. it will divide
the components by the norm. no verification for zero is
done.
itkPoint has the following method:
- Point.SetToMedian( A, B) the calling point is set to
the median of the two points given as parameters
- Point.SetToBarycentricCombination( A, B, a )
the calling point is set to a*A + (1-a)*B
- Point.SetToBarycentricCombination( A, B, C, a, b )
the calling point is set to a*A+b*B+(1-a-b)*C
Luis
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