[CMake] Detecting 32/64 bit systems

[Dominik Szczerba]

Quite right.

So you claim that on Windows CMAKE_SIZEOF_VOID will tell me the
*target* build system, not the physical one, while it will mach
CMAKE_SYSTEM_PROCESSOR if the both are the same?

Many thanks for the clarification.

Dominik

On Sat, Feb 12, 2011 at 6:34 PM, Ryan Pavlik <rpavlik at iastate.edu> wrote:
> CMAKE_SIZEOF_VOID_P will tell you the difference between target bit-widths:
> 8 (for 64 bit) vs 4 (for 32 bit) - remember that just because you're running
> on a 64-bit system doesn't mean you're compiling a 64-bit binary.
> Ryan
>
> On Sat, Feb 12, 2011 at 11:29 AM, Dominik Szczerba <dominik at itis.ethz.ch>
> wrote:
>>
>> OK, got it experimentally. You have
>>
>> CMAKE_SYSTEM_PROCESSOR
>>
>> But wait, is the description below correct?
>>
>> http://www.cmake.org/Wiki/CMake_Useful_Variables
>>
>> Opposed to the explanations there, which I saw, but took as not what I
>> need, on my systems it amounts to i686 and x86_64, exactly what I
>> need.
>>
>> Dominik
>>
>> On Sat, Feb 12, 2011 at 6:19 PM, Dominik Szczerba <dominik at itis.ethz.ch>
>> wrote:
>> > Hi,
>> >
>> > I can't really find a clear solution in google: how would one go about
>> > detecting if the system is 32 or 64 bit? There are UNIX, WIN32 etc.
>> > flags, but nothing really for the architecture.
>> >
>> > Thanks a lot,
>> > Dominik
>> >
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> Ryan Pavlik
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> Iowa State University
>
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