<div dir="ltr">Thank you Samuel,<div><br></div><div>The "Clip-> Box" filter is definitely better, but it still cuts out portions of arrows. I am ataching a picture for illustration.</div><div><br></div><div><img src="cid:ii_15820e79c0e47968" alt="Inline image 1" width="472" height="334"><br></div><div><br></div><div>These issues seem to arise because the arrows are not seen as unitary objects, but as a tube and a pointer. Using cones instead of arrows is not useful, the cones do not respect the start and end points same as arrows.</div><div><br></div><div>Dorian</div></div><div class="gmail_extra"><br><div class="gmail_quote">On Tue, Nov 1, 2016 at 12:03 PM, Samuel Key <span dir="ltr"><<a href="mailto:samuelkey@bresnan.net" target="_blank">samuelkey@bresnan.net</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
  
    
  
  <div bgcolor="#FFFFFF" text="#000000">
    <p><tt>Dorian,</tt></p>
    <p><tt>Try the CLIP filter with a box.</tt></p>
    <p><tt>Sam Key</tt><br>
    </p><div><div class="h5">
    <br>
    <div class="m_3901862981593099601moz-cite-prefix">On 11/1/2016 9:34 AM, Dorian Pustina
      wrote:<br>
    </div>
    </div></div><blockquote type="cite"><div><div class="h5">
      <div dir="ltr">Thank you both for the suggestions. I managed to
        have the arrows via python calculator, but couldn't make the
        Temporal Particles to Pathlines filter produce arrows.
        <div><br>
        </div>
        <div>Can I bug you with another question?</div>
        <div><br>
        </div>
        <div>I want to apply a Slice filter to see the arrows that
          depart from that slice. But the filter in Paraview just cuts
          through the objects in that slice, it doesn't show the whole
          arrows. It also does not have any tolerance (i.e., to pick
          points 2mm before and after the slice). Is there another way
          to get a slice with full arrows, and have some tolerance to
          pick up more points before and after the slice?</div>
        <div><br>
        </div>
        <div><br>
        </div>
        <div class="gmail_extra"><br>
          <div class="gmail_quote">On Tue, Nov 1, 2016 at 10:20 AM,
            Moreland, Kenneth <span dir="ltr"><<a href="mailto:kmorel@sandia.gov" target="_blank">kmorel@sandia.gov</a>></span> wrote:<br>
            <blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
              <div link="#0563C1" vlink="#954F72" lang="EN-US">
                <div class="m_3901862981593099601m_-6606603899294626353m_-3876113942550507440WordSection1">
                  <p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1f497d">If
                      you want to draw a line from point positions at
                      two subsequent time steps, you can use the
                      Temporal Particles To Pathlines filter, which
                      traces a line behind particles as they move
                      through space and time. When you use this filter
                      for your purposes, set Mask Points to 1 and Max
                      Track Length to 2. (You can increase Max Track
                      Length to lengthen the line to connect more than 2
                      timesteps.) Note that you will not see any lines
                      until you step time.</span></p>
                  <p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1f497d"> </span></p>
                  <p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1f497d">The
                      Temporal Particles to Pathlines filter actually
                      has two outputs. The first, named Pathlines,
                      contains the lines. The second, named Particles,
                      is a point at the end position of the line. You
                      can add a glyph to this output to create
                      arrow-like filters.</span></p>
                  <p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1f497d"> </span></p>
                  <p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1f497d">-Ken</span></p>
                  <p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1f497d"> </span></p>
                  <p class="MsoNormal"><b><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">From:</span></b><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">
                      ParaView [mailto:<a href="mailto:paraview-bounces@paraview.org" target="_blank">paraview-bounces@parav<wbr>iew.org</a>]
                      <b>On Behalf Of </b>Dorian Pustina<br>
                      <b>Sent:</b> Monday, October 31, 2016 8:09 PM<br>
                      <b>To:</b> <a href="mailto:paraview@paraview.org" target="_blank">paraview@paraview.org</a><br>
                      <b>Subject:</b> [EXTERNAL] [Paraview] Compute line
                      between coordinates</span></p>
                  <span>
                    <p class="MsoNormal"> </p>
                    <div>
                      <p class="MsoNormal">Hello everyone,</p>
                      <div>
                        <p class="MsoNormal"> </p>
                      </div>
                      <div>
                        <p class="MsoNormal">I am working on visualizing
                          some brain imaging data. I have a bunch of
                          points in 3D space, which have two sets of
                          coordinates: x1/y1/z1 and x2/y2/z2. All I need
                          is to show arrow glyphs starting from the
                          first coordinate and ending to the second
                          coordinate. I currently import the data as
                          csv. I tried using the time series option, and
                          I can loop through the two time points, but
                          can't find how to model a line or an arrow for
                          each point between the two times. I also tried
                          to compute what is called "velocity fields",
                          that is a set of 3 scalar factors that if
                          multiplied with the original coordinates would
                          yield the second coordinate (using
                          Calculator):</p>
                      </div>
                      <div>
                        <p class="MsoNormal">iHat*X snapped+jHat*Y
                          snapped+kHat*Z snapped</p>
                      </div>
                      <div>
                        <p class="MsoNormal"> </p>
                      </div>
                      <div>
                        <p class="MsoNormal">Still, I don't get
                          reasonable results. The problem looks trivial
                          but I couldn't find any solution online after
                          hours of search. It is not even clear to me
                          what does the above formula do exactly.</p>
                      </div>
                      <div>
                        <p class="MsoNormal"> </p>
                      </div>
                      <div>
                        <p class="MsoNormal">Can someone help if this is
                          possible?</p>
                      </div>
                      <div>
                        <p class="MsoNormal"> </p>
                      </div>
                      <div>
                        <p class="MsoNormal">Dorian</p>
                      </div>
                    </div>
                  </span></div>
              </div>
            </blockquote>
          </div>
          <br>
        </div>
      </div>
      <br>
      <fieldset class="m_3901862981593099601mimeAttachmentHeader"></fieldset>
      <br>
      </div></div><span class=""><pre>______________________________<wbr>_________________
Powered by <a class="m_3901862981593099601moz-txt-link-abbreviated" href="http://www.kitware.com" target="_blank">www.kitware.com</a>

Visit other Kitware open-source projects at <a class="m_3901862981593099601moz-txt-link-freetext" href="http://www.kitware.com/opensource/opensource.html" target="_blank">http://www.kitware.com/<wbr>opensource/opensource.html</a>

Please keep messages on-topic and check the ParaView Wiki at: <a class="m_3901862981593099601moz-txt-link-freetext" href="http://paraview.org/Wiki/ParaView" target="_blank">http://paraview.org/Wiki/<wbr>ParaView</a>

Search the list archives at: <a class="m_3901862981593099601moz-txt-link-freetext" href="http://markmail.org/search/?q=ParaView" target="_blank">http://markmail.org/search/?q=<wbr>ParaView</a>

Follow this link to subscribe/unsubscribe:
<a class="m_3901862981593099601moz-txt-link-freetext" href="http://public.kitware.com/mailman/listinfo/paraview" target="_blank">http://public.kitware.com/<wbr>mailman/listinfo/paraview</a>
</pre>
    </span></blockquote>
    <br>
  </div>

<br>______________________________<wbr>_________________<br>
Powered by <a href="http://www.kitware.com" rel="noreferrer" target="_blank">www.kitware.com</a><br>
<br>
Visit other Kitware open-source projects at <a href="http://www.kitware.com/opensource/opensource.html" rel="noreferrer" target="_blank">http://www.kitware.com/<wbr>opensource/opensource.html</a><br>
<br>
Please keep messages on-topic and check the ParaView Wiki at: <a href="http://paraview.org/Wiki/ParaView" rel="noreferrer" target="_blank">http://paraview.org/Wiki/<wbr>ParaView</a><br>
<br>
Search the list archives at: <a href="http://markmail.org/search/?q=ParaView" rel="noreferrer" target="_blank">http://markmail.org/search/?q=<wbr>ParaView</a><br>
<br>
Follow this link to subscribe/unsubscribe:<br>
<a href="http://public.kitware.com/mailman/listinfo/paraview" rel="noreferrer" target="_blank">http://public.kitware.com/<wbr>mailman/listinfo/paraview</a><br>
<br></blockquote></div><br></div>