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<p>Hey Tim,</p>
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<p>thanks for your reply! T<span style="font-size: 10pt;">he Mesh </span><span style="font-size: 10pt;">Quality filter indeed provides the Edge </span><span style="font-size: 10pt;">Ratio for all tetrahedral elements, a single value calculated for every cell
using </span><span style="font-size: 10pt;">the values I actually need. There must be a way to access them specifically (<span style="font-family: Arial, Helvetica, sans-serif; font-size: 13.3333px;">min/max/mean edge length</span>) or a workaround to obtain this
information. <span style="font-family: Arial, Helvetica, sans-serif; font-size: 13.3333px;">Does anybody know how I could do that? Thank you for your help!</span></span></p>
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<p>Best, Tom</p>
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<div id="divRplyFwdMsg" dir="ltr"><font face="Calibri, sans-serif" color="#000000" style="font-size:11pt"><b>From:</b> Tim Gallagher <tim.gallagher@gatech.edu><br>
<b>Sent:</b> Monday, January 25, 2016 8:13 PM<br>
<b>To:</b> Fastl, Thomas<br>
<b>Cc:</b> paraview@paraview.org<br>
<b>Subject:</b> Re: [Paraview] Calculate Edge Lengths in Unstructured Grid</font>
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Thomas,<br>
<br>
You can use the MeshQuality filter to compute the Edge Ratio for tetrahedral cells. This will give you a field called Quality in your dataset. You can then compute the statistics on it using other filters as needed.
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That should do what you are looking for. The definitions used in the MeshQuality filter can be found at: http://www.vtk.org/Wiki/images/6/6b/VerdictManual-revA.pdf<br>
<br>
Tim<br>
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<b>From: </b>"Thomas Fastl" <thomas.fastl@kcl.ac.uk><br>
<b>To: </b>paraview@paraview.org<br>
<b>Sent: </b>Monday, January 25, 2016 1:02:35 PM<br>
<b>Subject: </b>[Paraview] Calculate Edge Lengths in Unstructured Grid<br>
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<p>Hello Community,</p>
<p><br>
</p>
<p>I'm trying to calculate the min/max/mean edge length (or even an edge length distribution) in a tetrahedral element mesh specified as an unstructured grid in Paraview. I've played with the 'Extract Edges' filter, however, wasn't successful so far. Does anybody
know how I could do that? Thank you for your input! </p>
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</p>
<p>Best, Thomas Fastl</p>
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