[CMake] Getting library name from library target to pass to legacy Makefile

[Marc CHEVRIER]

An alternate solution is to use generator expression TARGET_LINKER_FILE_NAME because the linker is also able to use full path names rather than radical names as library input.
Le 22 juil. 2019 à 17:55 +0200, Dustyn Blasig <dustyn at blasig.us>, a écrit :
> Thanks, Marc. That is exactly what I need, but I'm stuck with 3.12.4 for the foreseeable future. Is there a way to get the equivalent behavior in older versions?
>
> > On Mon, Jul 22, 2019 at 1:04 AM Marc CHEVRIER <marc.chevrier at gmail.com> wrote:
> > > You can use generator expression TARGET_FILE_BASE_NAME, available with version 3.15.
> > > Le 22 juil. 2019 à 05:24 +0200, Dustyn Blasig <dustyn at blasig.us>, a écrit :
> > > > Hi All,
> > > >
> > > > I am integrating a legacy Makefile with our CMake flow, and need to pass the name of a CMake library target to the Makefile via add_custom_command(). The library uses the OUTPUT_NAME property to override the default.
> > > >
> > > > add_library(foo_lib SHARED ...)
> > > > set_target_properties(foo_lib PROPERTIES OUTPUT_NAME foo) # Generates libfoo.so
> > > > add_custom_command(... COMMAND make ... FOO_LIB_LINKER_NAME=<????> ...)
> > > >
> > > > I need <????> to be the value passed to -l of g++, namely -lfoo or -lfood for debug builds. I can't seem to find an expression/property that gives this shortened name. The generator expressions like TARGET_LINKER_FILE_NAME give libfoo.so.
> > > >
> > > > What is the appropriate way to get just the stem of the library with the configuration-specific suffix if needed?
> > > >
> > > > Thanks!
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