[CMake] Undefine a project()

[David Cole]

It is customary, but not enforced, to have only one project command in a
CMakeLists.txt file.

The project command maps to generated *.sln files for the Visual Studio
generators.

All targets defined after the project command in the same CMakeLists.txt
file, or any included by virtue of add_subdirectory, will appear in the
*.sln file that corresponds to that project command.

To prevent this, simply organize things differently.

There's no way with existing CMake to undefine a project or target.


HTH,
David


On Tue, May 22, 2012 at 2:49 PM, Robert Dailey <rcdailey.lists at gmail.com>wrote:

> Hi,
>
> I was wondering if there is a way to undefined a project(). I want to do
> this to prevent projects from being included in a solution when I generate
> for Visual Studio. Example:
>
> project( A )
> add_executable( A a.cpp )
> project( B )
> add_executable( B b.cpp )
> add_executable( C c.cpp )
>
> I don't want B to be in A's solution when I open A.sln. I'm assuming this
> is the behavior, unless project(B) call cancels out project(A)?
>
> Also, I don't want project C to appear in either A or B solutions.
>
> The reason why I'm doing this is because I have setup my CMake scripts to
> allow a solution file to be generated for executables (so I can open each
> executable solution in different instances of visual studio, with ONLY that
> executable + dependency projects in it). However, since sometimes multiple
> executable projects can be defined in the same directory, or other
> libraries that aren't a dependency of that executable, I do not want those
> to be included in the project().
>
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